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144x^2-100=(12x+10)(12x-10)
We move all terms to the left:
144x^2-100-((12x+10)(12x-10))=0
We use the square of the difference formula
144x^2+144x^2+100-100=0
We add all the numbers together, and all the variables
288x^2=0
a = 288; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·288·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{576}=0$
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